lazmary2002
lazmary2002 lazmary2002
  • 10-04-2018
  • Mathematics
contestada

Can someone help me i'm not sure what to do

Can someone help me im not sure what to do class=

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springwilliams0
springwilliams0 springwilliams0
  • 10-04-2018
they give the forumula you need to use to determine the area, its A=6s^2

plug in 1/3 as s, A=6(1/3)^2
now solve for A

(1/3)^2= 1/9
A=6(1/9)
im going to cross multiply these two numbers
A=2/3

the answer is C. 2/3 square foot

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