karsynraine3687 karsynraine3687
  • 07-03-2018
  • Mathematics
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Fill in the table and guess the value of the limit: \lim\limits_{x \to 3} f(x), where f(x)= \frac {x^3 - 27} {x^2 - 9}

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evgeniylevi
evgeniylevi evgeniylevi
  • 07-03-2018
Try this option:
[tex] \lim_{x \to 3} \frac{x^3-27}{x^2-9} = \lim_{x \to 3} \frac{x^2+3x+9}{x+3}= \frac{27}{6}= \frac{9}{2} [/tex]
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