GIVEN:
X: Height.
(X + 5): Base.
Area: 52 yd².
SOLVING:
Area formula: [tex]\boxed{A= \dfrac{(base)*(height)}{2}}[/tex]
[tex] \dfrac{X(X + 5)}{2}=52\\ \\X(X+5)=2(52)\\ \\X ^{2}+5X=104\\ \\X ^{2}+5X-104=0\\ \\(X+13)(X-8)=0\\ \\ \\X_{1}=-13\quad\to\ Negative\ value\ discarded.\\ \\X_{2}=8\quad\checkmark\ Height.\ ===>\ ANSWER[/tex]
The base of triangular garden is 5 yards longer than the height:
[tex]8+5=13\quad\checkmark\ Base[/tex]
HOPE THIS HELPS...!!
