tinab4daniel20oxk8pv
tinab4daniel20oxk8pv
09-10-2017
Mathematics
contestada
Solve B+B=2 B+C=5 B+C*2=
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choixongdong
choixongdong
09-10-2017
B+B=2
2B = 2
B = 1
substitute B = 1
B+C=5
1 + C = 5
C = 5 -1
C = 4
so
B+C*2
= 1 + 4*2
= 1 + 8
= 9
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