smith123450 smith123450

08-05-2024
Chemistry

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Calculate the change in enthalpy for the following reaction: Ca3(PO4)2(s) + 2H2SO4(l) --> 3CaSO4(s) + 2H3PO4(l) ΔHf Ca3(PO4)2= -4126 ΔHf H2SO4= -814 ΔHf CaSO4= -1433 ΔHf H3PO4= -1267 ΔHreaction= kJ/mol Is this reaction endothermic or exothermic?

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