ginadesor34911 ginadesor34911
  • 08-02-2024
  • Computers and Technology
contestada

var myName = 'any-name-entered'; //do not take this string literally - It should work for Dave or Harold or Sue or whoever enters their name.
for (var x = 0; x < myName.length; x++) {
(myName[x]);
}
a) myName.length;
b) myName.size;
c) myName.count;
d) myName.chars;

Respuesta :

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