murawskik murawskik
  • 06-03-2017
  • Mathematics
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Sec^4x-tan^4x=sec^2x+tan^2x

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LammettHash
LammettHash LammettHash
  • 06-03-2017
[tex]\sec^4x-\tan^4x=(\sec^2x-\tan^2)(\sec^2x+\tan^2x)=\sec^2x+\tan^2x[/tex]

since [tex]\tan^2x+1=\sec^2x[/tex].
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