caydence4630
caydence4630 caydence4630
  • 08-07-2022
  • Mathematics
contestada

Please help with this

Please help with this class=

Respuesta :

syahbanazacki
syahbanazacki syahbanazacki
  • 08-07-2022

Step-by-step explanation:

[tex] = \frac{14\pi}{6} [/tex]

[tex] = \frac{ \cancel{14}\pi}{ \cancel6} [/tex]

[tex] = \frac{7\pi}{3} [/tex]

[tex] = \frac{6\pi + \pi}{3} [/tex]

[tex] = \frac{6\pi}{3} + \frac{\pi}{3} [/tex]

[tex] = 2\pi + \frac{\pi}{3} [/tex]

[tex] = 0 + \frac{\pi}{3} [/tex]

[tex] = \frac{\pi}{3} \: \text{where} \: \frac{\pi}{3} < 2\pi[/tex]

The answer is B.

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