What is the final temperature of a 2.50 L system when its volume is reduced to 1.75 L if the initial temperature was 298 K?

Respuesta :

Answer:

208.6 K

Explanation:

V1/T1  =  V2/T2

T2 = T1 V2 / V1

            T  must be in K units

T2 = 298 * 1.75 / 2.5 = 208.6 K