Answer:
Below in bold.
Step-by-step explanation:
y = x^2-8x+6
y = (x - 4)^2 - 16 + 6
y = (x - 4)^2 - 10
So the vertex is at (4, -10)
The coefficient of x^2 of this function is 1 ( positive) so there will be a minimum value.
Minimum value = -10.
x-intercepts:
(x - 4)^2 - 10 = 0
(x - 4)^2 = 10
x - 4 = +/- √10
x = 4 +/- √10
- therefore there are 2 x-intercepts.
