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What is the equation of a line that is perpendicular to 2x+y=āˆ’4 and passes through the point (2, āˆ’8)?
please help!!!!!!!!!!!!!!

Respuesta :

Ata258

Answer:

y2=(1/2)x-9

Step-by-step explanation:

y= -2x-4

perpendicilar so multiplication of slope is -1

-2*m2=-1

m2=1/2

y2=(1/2)x+c need to passes trough (2,-8)

-8=(1/2)*2+c

-8=1+c

c=-9

y2=(1/2)x-9

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