Answer:
it's the very first anwer
Step-by-step explanation:
all you had to do was subtract the bottom exponents from the top, maintaining the sane base numbers
[tex] \frac{4 {}^{33 } \times {8}^{37} }{4 {}^{15 \times } 8 {}^{21} } \\ we \: know \: that \\ {a}^{m} \div {a}^{n} = (a) {}^{m - n} \\ \: = (4) {}^{33 - 15} \times (8) {}^{37 - 21} \\ = (4) {}^{18} \times (8) {}^{16} [/tex]
