Respuesta :

pjdemarco

Answer:

b. 0.2

Step-by-step explanation:

e and ln are inverse functions of each other

loneguy

[tex]\\\text{Let,}\\\\y = e^{\ln(0.2)}\\\\\implies \ln y = \ln\left[e^{\ln(0.2)}\right]\\\\\implies \ln y = \ln(0.2) \ln e\\\\\implies \ln y = \ln (0.2)~~~~;[\ln e = \text{log}_e e =1]\\\\\implies y = 0.2\\\\\implies e^{\ln(0,2)} = 0.2[/tex]

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