Answer:
Step-by-step explanation:
I suppose the question is to solve the equation
[tex]2x+3y+1+3ix=x-2y+(3+y)*i\\\\2x+3y+1+3ix-x+2y-3i-iy=0\\\\x+5y+1+i(3x-y-3)=0\\\\\Longrightarrow\\\\\left\{\begin{array}{ccc|c|c|}x+5y&=&-1&-3&1\\3x-y&=&3&1&5\\\end{array}\right.\\\\\\\left\{\begin{array}{ccc}-16y&=&6\\16x&=&14\\\end{array}\right.\\\\\\\left\{\begin{array}{ccc}x&=&\dfrac{14}{16}\\\\y&=&\dfrac{-6}{16} \\\end{array}\right.\\[/tex]
