Answer:
0.105 M
Explanation:
First we convert 25.3 grams of sucrose into moles, using sucrose's molar mass:
- Molar Mass of C₁₂H₂₂O₁₁ = 342.3 g/mol
- 25.3 g C₁₂H₂₂O₁₁ ÷ 342.3 g/mol = 0.0739 mol C₁₂H₂₂O₁₁
Now we calculate the molarity of the solution, using the given volume and the calculated number of moles:
- Converting 705 mL ⇒ 705 mL / 1000 = 0.705 L
- Molarity = 0.0739 mol / 0.705 L = 0.105 M
