6a²+11x-10= (3a+5)(3a-2)
Answer:
Solution given:
6a²+11x-10
doing middle term factorisation
6a²+(15-4)x-10
6a²+15x-4x-10
3a(3a+5)-2(3a+5)
(3a+5)(3a-2)
Step-by-step explanation:
if
6a²+11x-10=0
(3a+5)(3a-2)=0
either
a=-5/3
it
a=⅔
