Answer:
[tex]\Delta T=57.01^{\circ} C[/tex]
Explanation:
Given that,
The mass of nickel, m = 70 g
Energy absorbed, Q = 1756 J
The specific heat of Nickel, c = 0.440 J/g °C
We know that,
The heat absorbed is given by :
[tex]Q=mc\Delta T\\\\\Delta T=\dfrac{Q}{mc}\\\\\Delta T=\dfrac{1756}{70\times 0.44}\\\\=57.01^{\circ} C[/tex]
So, the change in temperature is equal to [tex]57.01^{\circ} C[/tex].
