Answer:
The point lies outside the circle.
Step-by-step explanation:
To find where the point lies find the distance between the centre of the circle and the point :
[tex]Distance , QY = \sqrt{(4-1)^2 + (1-(-5))^2}[/tex]
[tex]= \sqrt{3^2 + 6^2}\\\\= \sqrt{9 + 36 } \\\\= \sqrt{45} = 6.71[/tex]
Since distance between Centre, Q and the point, Y is greater than the radius of the circle , the point lies outside the circle.
