fifififi38 fifififi38
  • 10-05-2021
  • Mathematics
contestada

How much money would you have if you invested $3000 at 6.25% annual interest, compounded daily for 2 years?

Respuesta :

ANCKPOP
ANCKPOP ANCKPOP
  • 11-05-2021

Answer:

[tex]A\simeq3399.41[/tex]

Step-by-step explanation:

The amount formula in compound interest is:

[tex]A=P(1+\frac{r}{n} )^{nt}[/tex]

where:

P = principal amount

r = annual interest

n = number of compounding periods

t = number of years

We already know that:

P = $3000

[tex]r = 6.25\% = \frac{6.25\%}{100\%}=0.0625[/tex]

t = 2

n = 365

Then,

[tex]A=3000(1+\frac{0.0625}{365} )^{(365)(2)}\\\\A=3000(1+\frac{0.0625}{365} )^{730}\\\\A=3399.408982\\\\A\simeq3399.41[/tex]

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