Answer:
x=0
Step-by-step explanation:
The axis of symmetry: [tex]x=\frac{-b}{2a}[/tex] when the equation is [tex]y=ax^2+bx+c[/tex]
The given equation is:
[tex]y=x^2-6[/tex]
To make the a and b values more easily identifiable, we can rewrite it like this:
[tex]y=1x^2+0-6[/tex]
Now, we can tell that a=1 and b=0. Plug these into the equation [tex]x=\frac{-b}{2a}[/tex] :
[tex]x=\frac{-(0)}{2(1)}\\x=0[/tex]
Therefore, the equation for the axis of symmetry for the parabola is x=0.
I hope this helps!
