Answer:
3557J is the heat lost by the water
Explanation:
Using the equation:
Q = m*C*ΔT
Where Q is change in heat
m is mass of substance (23g of water)
C is specific heat of the substance (4.18J/g°C)
And ΔT is change in temperature (68.0°C - 31.0°C = 37.0°C)
we can find the amount of heat lost as follows:
Q = 23g*4.18J/g°C*37°C
Q =
3557J is the heat lost by the water
