Respuesta :

rosie2276

Answer:

dy/dx= 7- 3x^-1/2

when X=1

dy/dx = 4

as it is a tangent M1=M2=4

now,

at gradient 4 and point (1,1)

equation of curve is ,

y-y1= m(x-x1)

or, y-1=4(x-1)

or, y-1=4x-4

or, y-4x= -3

or, 4x-y=3

samuelbutler23

Answer:

BRAINLEST ANSWER

Step-by-step explanation:

dy/dx=7-3x^-1/2

when x=1

Dy/dx=4

as it is a tangent M1=M2=4 now

at gradient 4 and point(1,1) equation of a curve is y-y1=m(x-x1)

or y-1=4(x-1)

or y-1=4x-4

or y-4x=-3

or 4x-y=3

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