gaboefcruz14 gaboefcruz14
  • 10-02-2021
  • Mathematics
contestada

The points (11, 13) and (7, 13) fall on a particular line. What is its equation in slope-intercept form?

Respuesta :

belgrad belgrad
  • 15-02-2021

Answer:

slope -intercept form y=mx+c

The equation of the straight line

                                 y = 0x +13

Step-by-step explanation:

Step(i):-

Given that the points

           (11 ,13) and (7,13)

The slope of the line

    [tex]m = \frac{y_{2}-y_{1} }{x_{2} -x_{1} } = \frac{13-13}{7-11} = \frac{0}{-4} =0[/tex]

Step(ii):-

Equation of the straight line passing through the point (11,13) and slope m=0

y - y₁ = m( x-x₁)

y - 13 =0(x-11)

y-13 =0

y =13

slope -intercept form y=mx+c

y = 0x +13

Answer Link

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