Answer:
x = 2/3 and y = 8/9
Step-by-step explanation:
If a parallelogram INDY has diagonals that intersects at P, then O bisects ID and YN
Hence IP = PD and NP = YP
Given
IP=3x
DP = 6x - 2
NP = 3y and
YP=7x-2,
Substitute
3x = 6x-2
3x-6x = -2
-3x = -2
x = 2/3
x = 0.67
Also NP = YP
3y = 7x-2
3y = 7(2/3) - 2
3y = 14/3 - 2
3y = 14-6/3
3y = 8/3
9y = 8
y = 8/9
Hence x = 2/3 and y = 8/9
