Answer:
[tex]a_{n}[/tex] = 6n - 1
Step-by-step explanation:
There is a common difference d between consecutive terms in the sequence
d = 11 - 5 = 17 - 11 = 23 - 17 = 6
This indicates the sequence is arithmetic with n th term
[tex]a_{n}[/tex] = a₁ + (n - 1)d
where a₁ is the first term and d the common difference
Here a₁ = 5 and d = 6 , then
[tex]a_{n}[/tex] = 5 + 6(n - 1) = 5 + 6n - 6 = 6n - 1
