eschopi eschopi
  • 10-01-2021
  • Mathematics
contestada

[tex]\frac{a-3b}{a+2b} = \frac{4}{3}[/tex]

what is the value of a:b??

Respuesta :

MrRoyal
MrRoyal MrRoyal
  • 15-01-2021

Answer:

[tex]a:b = -17:1[/tex]

Step-by-step explanation:

Given

[tex]\frac{a-3b}{a+2b} = \frac{4}{3}[/tex]

Required

Find a:b

[tex]\frac{a-3b}{a+2b} = \frac{4}{3}[/tex]

Cross Multiply

[tex]3(a-3b) = 4(a+2b)[/tex]

Open brackets

[tex]3a - 9b = 4a + 8b[/tex]

Collect Like Terms

[tex]3a - 4a = 8b+9b[/tex]

[tex]-a = 17b[/tex]

Divide through by -b

[tex]\frac{-a}{-b} = \frac{17b}{-b}[/tex]

[tex]\frac{a}{b} = \frac{17}{-1}[/tex]

[tex]\frac{a}{b} = \frac{-17}{1}[/tex]

Represent as a ratio

[tex]a:b = -17:1[/tex]

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