Answer:
[tex]\huge\boxed{-10<x<0\to x\in(-10;\ 0)}[/tex]
Step-by-step explanation:
[tex]5<-2x+5<25\qquad|\text{subtract 5 from all sides}\\\\0<-2x<20\qquad|\text{change all signs}\\\\0>2x>-20\to -20<2x<0\qquad|\text{divide all sides by 2}\\\\-\dfrac{20}{2}<\dfrac{2x}{2}<\dfrac{0}{2}\\\\-10<x<0[/tex]
