Complete question is;
What is the electrical potential at the surface of gold nucleus? The radius of a gold atom is 6.6 × 10^(-5) m and atomic number z = 79.
Answer:
172.36 × 10^(-5) V
Explanation:
We are given;
Radius; r = 6.6 × 10^(-5) m
Atomic number; Z = 79
Formula for Electric potential here is;
V = kZe/r
Where;
e is charge on proton = 1.6 × 10^(-19) C
k has a constant value of 9 × 10^(9) N⋅m²/C²,
Thus;
V = (79 × 1.6 × 10^(-19) × 9 × 10^(9))/(6.6 × 10^(-5))
V = 172.36 × 10^(-5) V
