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Consider a process carried out on 1.00 mol of a monatomic ideal gas by the following two different pathways.

The first pathway is A (3.00 atm, 20.0 L) to C (1.00 atm, 20.0 L) to D (1.00 atm, 50.0 L); and the second pathway is A (3.00 atm, 20.0 L) to B (3.00 atm, 50.0 L) to D (1.00 atm, 50.0 L). In each case, the gas is taken from state A to state D.

Required:
Calculate wAB.

Respuesta :

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Answer:

90 L.atm

Explanation:

From the given information:

The first pathway:

A( 3 atm, 20 L) → C ( 1 atm, 20 L) → D (1 atm, 50 L)

The second pathway:

A(3 atm, 20 L) → B( 3 atm, 50 L) → D ( 1 atm, 50 L)

Since the number of moles = 1.00 moles

To find wAB;

A → B  shows the conversion happening at constant pressure ;

∴

wAB = pressure × volume change

wAB = P(V₂ - V₁)

wAB =  3 atm ( 50 L - 20 L)

wAB =  3 atm ( 30 L)

wAB = 90 L.atm