Respuesta :

maxbinom20

Answer:

(1 / cot²θ) + secθ cosθ  

(1 / cotθ) == tanθ

Therefore

tan²θ + secθ cosθ

secθ == (1 / cos θ)

Therefore

tan²θ + (1 / cosθ) cosθ

The cosθ 's cancel out

Therefore

tan²θ + 1

tan²θ + 1 == sec²θ

Therefore

sec²θ is the simplified answer

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