kamillanandin13 kamillanandin13

07-12-2020
Mathematics

contestada

4(3k + 2) = 6(2k – 1) +14

Respuesta :

devishri1977 devishri1977

07-12-2020

Answer:

This equations has infinite solutions

Step-by-step explanation:

Use distributive property

4(3k + 2) = 6(2k – 1) +14

4*3k + 4*2 = 6*2k - 6*1 + 14

12k + 8 = 12k - 6 + 14

12k + 8 = 12k + 8

So, this equations has infinite solutions

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