Answer:
a([tex]b^{2}[/tex]+[tex]c^{2}[/tex]) = = -13
Step-by-step explanation:
Given that a = -1, b=2 and c= -3
find the value of a([tex]b^{2}[/tex]+[tex]c^{2}[/tex])
Just substitute the values given for each variable
a([tex]b^{2}[/tex]+[tex]c^{2}[/tex]) = (-1)([tex]2^{2}[/tex]+[tex](-3)^{2}[/tex]) ; do the exponents first
a([tex]b^{2}[/tex]+[tex]c^{2}[/tex]) = (-1)(4+9)=(-1)(13) ; now add inside the parenthesis;
a([tex]b^{2}[/tex]+[tex]c^{2}[/tex]) = -13 ; and multiply by -1
