Answer:
f(y) = y
g(y) = y - 6
Step-by-step explanation:
[tex]\dfrac{y^2+6y}{y^2-36}\qquad\qquad\qquad\qquad y\ne6\,,y\ne-6 \\\\ \\\dfrac{y^2+6y}{y^2-36}=\dfrac{y\cdot y+6\cdot y}{y^2-6^2}=\dfrac{y(y+6)}{(y+6)(y-6)}=\dfrac{y}{(y-6)}\\\\\\f(y)=y\\\\g(y)=y-6[/tex]
