Answer:
44.9 m
Explanation:
For ballistic motion in x-y coordinates, an appropriate equation can be ...
y(x) = -4.9(x·sec(α)/v)² +tan(α)x + h0
where α is the angle of launch from the horizontal, and v is the magnitude of the launch velocity.
Here, we have v = 15 m/s, and α = 0, so the equation reduces to ...
y = -4.9/225x^2 +44
For y = 0, we can find x to be ...
x^2 = (44×225/4.9) ≈ 2020.41
x ≈ 44.949
The stone hits the ground about 44.9 meters from the base of the cliff.
