Answer:
[tex]\huge\boxed{\dfrac{40x^3y^6}{-8x^2y}=-5xy^5}[/tex]
Step-by-step explanation:
[tex]\dfrac{40x^3y^6}{-8x^2y}=\dfrac{40}{-8}\cdot\dfrac{x^3}{x^2}\cdot\dfrac{y^6}{y}\\\\\text{use}\ \dfrac{a^n}{a^m}=a^{n-m}\\\\=-5x^{3-2}y^{6-1}=-5x^1y^5=-5xy^5[/tex]
