Answer:
removable
Step-by-step explanation:
f(x) = cos(1/x^2) at x = 0;
For the function f(x) = cos(1/x^2) let's substitute the value of 0 in for x...
= cos(1/(0)^2)
= cos(1/0)
Now remember that x/0 is undefined. Removable discontinuity is undefined at the point x₀, and hence our solution is "removable."
