Answer:
see explanation
Step-by-step explanation:
Using [tex]\sqrt{-1}[/tex] = i, then i² = ([tex]\sqrt{-1}[/tex] )² = - 1
and i³ = i² × i = - 1 × i = - i
also
[tex]i^{4}[/tex] = i² × i² = - 1 × - 1 = 1
We can surmise that i raised to any multiple of 4 will equal 1
Given
[tex]i^{35}[/tex] ( note 35 = 32 + 3 and 32 is a multiple of 4 ), thus
= [tex]i^{32+3}[/tex]
= 1 × i³ = - i
