benamarie5421 benamarie5421
  • 09-07-2020
  • Chemistry
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You start with 6 moles of an acid, 2 moles dissociate into the conjugate base, what is the percent ionization

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dsdrajlin
dsdrajlin dsdrajlin
  • 14-07-2020

Answer:

33 %

Explanation:

Step 1: Given data

Initial moles of the acid (nHA(0)): 6 mol

Moles of the conjugate base at equilibrium (nA⁻(eq))

Step 2: Write the balanced generic acid dissociation reaction

HA(aq) ⇄ A⁻(aq) + H⁺(aq)

Step 3: Calculate the percent ionization

We will use the following expression.

[tex]\alpha = \frac{nA^{-}(eq)}{nHA(0)} \times 100 \% = \frac{2mol}{6mol} \times 100 \% = 33 \%[/tex]

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