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  • 09-06-2020
  • Mathematics
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Algebra 2 can anyone help??

Algebra 2 can anyone help class=

Respuesta :

surjithayer10 surjithayer10
  • 09-06-2020

Answer:

Step-by-step explanation:

cot θ=-9.68

cotθ is negative

so θ lies in 2nd or 4th quadrant.

tan θ=-1/9.68

θ=tan ^{-1}(-1/9.68)≈174.1°,354.1°

3.

sec θ=-9.13+5=-8.13

sec θ is negative so θ lies in 2nd or 3rd quadrant.

cos θ=(-1/8.13)

θ=cos^{-1}(-1/8.13)≈97.1°

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