avelasco024 avelasco024
  • 08-06-2020
  • Mathematics
contestada

Solve the following equation 4×6x−7=1 x= log8log6 x= log2log6 x= log6log8 x= log6log2

Respuesta :

warylucknow warylucknow
  • 15-06-2020

Answer:

The value of x is [tex]x=\frac{\log(2)}{\log(6)}[/tex].

Step-by-step explanation:

Solve the equation as follows:

[tex]4\times 6^{x}-7=1[/tex]

     [tex]4\times 6^{x}=7+1[/tex]

           [tex]6^{x}=\frac{8}{4}[/tex]

           [tex]6^{x}=2[/tex]

Take log on both sides.

[tex]\log(6^{x})=\log(2)[/tex]

[tex]x\log (6)=\log(2)[/tex]

        [tex]x=\frac{\log(2)}{\log(6)}[/tex]

Thus, the value of x is [tex]x=\frac{\log(2)}{\log(6)}[/tex].

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