Valishati Valishati

09-04-2020
Mathematics

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Which differential equation has y=2e^(x) as a solution?

Which differential equation has y2ex as a solution class=

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amna04352 amna04352

09-04-2020

Answer:

A

Step-by-step explanation:

y = 2e^x

y' = 2e^x

y" = 2e^x

A) (1 - x)(2e^x) + x(2e^x) - (2e^x)

= 2e^x - 2xe^x + 2xe^x - 2e^x

= 2e^x - 2e^x - 2xe^x + 2xe^x

= 0

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