Answer: Option C) 0.64kPa
Explanation:
Given that,
Original volume V1 = 11.2 L
original pressure P1 = 0.860kPa
New volume V2 = 15.0 L
New pressure P2 = ?
Since pressure and volume are involved while temperature is constant, apply Boyle's law
P1V1 = P2V2
0.860 kPa x 11.2 L = P2 x 15.0L
9.632 kPaL = P2 x 15.0L
P2 = 9.632 kPaL / 15.0L
P2 = 0.64 kPa
Thus, the pressure of the gas is 0.64kPa
