Answer:
389.48g of Fe
Explanation:
This is a stoichiometric reaction. First write a balanced equation of reaction: Fe2O3+3CO==>2Fe+3CO2
Since Fe2O3 and Fe are concerned with, calculate there masses in the balanced equation
Taking Molar mass of Fe and O to be 26 and 16 respectively.
Fe2O3 = (2×26) + (3×16)
=100g/mol
2Fe = 2×26
= 52
Therefore 100g of Fe2O3 gave 52g
749g of Fe2O3 will give
749×52/100
= 389.48g of Fe
