ansleighhall83 ansleighhall83

08-03-2020
Mathematics

contestada

What is the equation of a line parallel to y=-2x+10 that contains (6,8)

Respuesta :

miljanamilovanovic12 miljanamilovanovic12

08-03-2020

Answer:

y=-2x+20

Step-by-step explanation:

Line is parallel to y=-2x+10,then slope that line is - 2=k.

A(6,8).. x1=6,y1 =8

y-y1=k(x-x1)

y-8=-2(x-6)

y-8=-2x+12

y=-2x+12+8

y=-2x+20

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