Answer:
p = 5 and p = -11
Step-by-step explanation:
Note that the given (p+3)2−64 is the difference of two squares, for which there is the formula
(a^2 - b^2) = (a - b)(a + b).
Thus, (p+3)2−64 = [(p + 3) - 8][(p + 3) + 8]
and these last two results simplify to [p - 5][p + 11].
Setting these last two factors = 0 individually yields p = 5 and p = -11.
