pranavram2006
pranavram2006 pranavram2006
  • 09-02-2020
  • Mathematics
contestada

6v^2+24=0 find roots of equation

Respuesta :

Hrishii
Hrishii Hrishii
  • 09-02-2020

Step-by-step explanation:

[tex]6 {v}^{2} + 24 = 0 \\ \\ \therefore \: 6 {v}^{2} = - 24 \\ \\ \therefore \: {v}^{2} = \frac{ - 24}{6} \\ \\ \therefore \: {v}^{2} = - 4

\\ \\ \therefore \: {v}^{2} = 4\times - 1

\\ \\ \therefore \: {v} =\pm \sqrt {4} \times \sqrt{- 1}

\\ \\ \therefore \: {v} =\pm 2 \times i

\\ \\ \therefore \: {v} = \pm \sqrt{2} i[/tex]

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