Sawhneyyash1
Sawhneyyash1 Sawhneyyash1
  • 09-02-2020
  • Mathematics
contestada

Given (8x+3k)(9x−2)=0, the product of all solutions is (−3). Find k.

Respuesta :

jimrgrant1 jimrgrant1
  • 09-02-2020

Answer:

k = 36

Step-by-step explanation:

Given

(8x + 3k)(9x - 2) = 0

Equate each factor to zero and solve for x

9x - 2 = 0 ⇒ 9x = 2 ⇒ x = [tex]\frac{2}{9}[/tex]

8x + 3k = 0 ⇒ 8x = - 3k ⇒ x = [tex]\frac{-3k}{8}[/tex]

The product of the solutions = - 3, thus

[tex]\frac{2}{9}[/tex] × - [tex]\frac{3k}{8}[/tex] = - 3, that is

- [tex]\frac{6k}{72}[/tex] = - 3 ( multiply both sides by 72 )

- 6k = - 216 ( divide both sides by - 6 )

k = 36

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