Answer:
[tex]W=(x-6)\ m[/tex]
Step-by-step explanation:
we know that
The area of rectangle is equal to
[tex]A=LW[/tex]
we have
[tex]A=(x^{2} -11x+30)\ m^2[/tex]
[tex]L=(x-5)\ m[/tex]
substitute the given values in the formula of area
[tex](x^{2} -11x+30)=(x-5)W[/tex]
Remember that
[tex]x^{2} -11x+30=(x-5)(x-6)[/tex] ----> by completing the square
substitute
[tex](x-5)(x-6)=(x-5)W[/tex]
Simplify
[tex]W=(x-6)\ m[/tex]
