FluffyHook139 FluffyHook139

08-01-2020
Chemistry

contestada

4. 213.4 grams of NaNO3 contain how many moles?

Respuesta :

josshyaby josshyaby

08-01-2020

Answer:

Explanation:

mass of NaNO3 = 213.4g

Molar mass = {23 + 14 + 3(16)}

= 23 + 14 + 48

= 85g/mol

Amount = mass/molar mass

= 213.4/85

= 2.5moles of NaNO3

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