Answer:
two real solutions (Answer C)
Step-by-step explanation:
You can study the discriminator of this expression to find your answer.
Recall that the discriminator of a quadratic equation of the form: [tex]ax^2+bx+c=0[/tex] is: [tex]b^2-4ac[/tex]
So for this equation, [tex]a=12, \,b=1, \,and \,c=-1[/tex]
Therefore, the discriminator gives: [tex](1)^2-4(12)(-1)=49[/tex] which is larger than zero.
This tells us that the equation has two real solutions.
